★ wanayoo — archive 1999 http://www.php.net/manual/function.list.php

	Arrays
		array
		array_count_values
		array_flip
		array_keys
		array_merge
		array_pad
		array_pop
		array_push
		array_reverse
		array_shift
		array_slice
		array_splice
		array_unshift
		array_values
		array_walk
		arsort
		asort
		compact
		count
		current
		each
		end
		extract
		in_array
		key
		krsort
		ksort
		list
		next
		pos
		prev
		range
		reset
		rsort
		shuffle
		sizeof
		sort
		uasort
		uksort
		usort

Manual: list

ksort

list

list -- Assign variables as if they were an array

Description

void list(...);

Like array(), this is not really a function, but a language construct. list() is used to assign a list of variables in one operation.
Example 1. list() example
1 2 <table> 3 <tr> 4 <th>Employee name</th> 5 <th>Salary</th> 6 </tr> 7 8 <?php 9 10 $result = mysql($conn, "SELECT id, name, salary FROM employees"); 11 while (list($id, $name, $salary) = mysql_fetch_row($result)) { 12 print(" <tr>\n". 13 " <td><a href=/old?u=http%3A%2F%2Fwww.php.net%2Fmanual%2F%5C&y=1999"info.php3?id=$id\">$name</a></td>\n". 14 " <td>$salary</td>\n". 15 " </tr>\n"); 16 } 17 18 ?> 19 20 </table> 21

See also: each(), array().

User Contributed Notes: list

arni@linux.is
23-Aug-1999 08:53

I've been trying to put the field names of the rows I want to select from the table in a $fields variable, like this:<br><br>

$fields = 'id, name, salary';
$result = mysql($conn, "SELECT $fields FROM employees");
$fields = '$'.str_replace(", ",', $',"$fields");	

while (list($fields) = mysql_fetch_row($result)) {
    print("$fields");
}

<br><br> I also tried to eval() the $values, but that does not seem to work either. I spent few hours trying to find out how to do this, but...there is no solution. list() re-creates the $values variable as a one variable, not three variables as shown in earlier code.

siggma@xs4all.be
08-Oct-1999 09:09

At first I thought that list(...) creates an array of references, so that

$a='x'; $b='y'; $c='z';
$d=list($a,$b,$c);
$d[1]='OK';
print $b;

would give 'OK', the new value of $b put there through the reference in $d[1]; But no, list(...) is a function that requires to be assigned an array to...

evergod@dcnetsolutions.net
20-Jan-2000 09:55

I am trying to edit a certain portion of a file, which has lines individually containing something like this:

user;name;email;score

I need to change the "score" part of one of those lines when I come to a specific "user". I tried to use a while loop with list($key, $val) and change the $val variable to one incremented when it came to $key == 4, but it seems like it did not change the value of it. I use implode() to put the variables back together... here is my code:

$fp = file("Agents/list.dat");   
while(list($key,$val)=each($fp)) 
{ 
	$array = explode(";",$val); 
	while(list($key2,$val2)=each($array)) 
		if ($key2 == 3)
		{
			$val2 = 1;
			$array2[$x+=1] = implode(";", $array);
		}
}

$newfp = implode("<br>\n", $array2);

print("$newfp");

gs@e-nova.com.sg
18-Feb-2000 02:32

Suppose a list of three items is returned and you are only interested in items one and three, you can skip assigning item two by

list($one, , $three) = some_function();

ksort

Site
Hosting:

Located in
United States

Elements of this website are subject to copyright.
Questions about installing or using PHP should be directed to one of the mailing lists.
Only questions about the website should be directed to webmaster@php.net.